How do you graph #f(x)= log_(5)(x)#?

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Answer 1 · 2016-03-02T15:19:19

solve for intercepts if any and additional points near the intercepts and know the asymptote

the given #y=log_5 x" " "#this is the logarithmic form
#5^y=x" " "# the exponential form

When x=1, y=0, so we have a point #(1,0)#

When y approaches a very negative number, x approaches zero.

Therefore, #x=0# is a vertical asymptote

see the graph of #y=log_5 x#

graph{y=log x/log 5[-20,20,-10,10]}

God bless....I hope the explanation is useful