How do you find all the zeros of #f(x) = -3(x+1/2)(x-4)^3#?

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Answer 1 · 2016-03-02T19:54:16

#x=-1/2# and #x=4#

if you have a product of several factors, and their product is zero is because at least one of them is zero:

Symbolically:

# abcdef=0 => a=0 or b=0 or c=0 or d=0 or e=0 or f=0#

So the zeros of #-3(x+1/2)(x-4)^3#

can be calculted by solving:

#x+1/2=0# and #x-4=0#

#x=-1/2# and #x=4#