Question

How do you find the standard form of `2x=2y^2-28` and what kind of a conic is it?

Answer 1

the General Form: `y^2-x-14=0`
the Standard Form or Vertex Form :`(y-0)^2=(x--14)`

Explanation:

it is a parabola which opens to the right
with center `C(h, k)=(-14, 0)`
Directrix : `x=-57/4`
Focus:`(-55/4, 0)`

graph{2x=2y^2-28[-20,20,-10,10]}

God bless .... I hope the explanation is useful..