Question

A triangle has sides A, B, and C. Sides A and B are of lengths `8` and `6`, respectively, and the angle between A and B is `(11pi)/12`. What is the length of side C?

Answer 1

`C=13,88`

Explanation:

`"use cosine theorem"`
`C^2=A^2+B^2-2*A*B*cos theta`
`C^2=8^2+6^2-2*8*6*cos 11 pi/12`
`C^2=64+36-96*(-0,966)`
`C^2=100+92,736`
`C=sqrt(192,736)`
`C=13,88`