How do you convert $(4, 3 \frac{π}{2})$ $(4, 3pi/2)$ to rectangular form?

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Answer 1 · 2016-03-10T10:34:13

$(4, \frac{3 π}{2})$ $(4,(3pi)/2)$ in polar coordinates is $(0, - 4)$ $(0,-4)$ in rectangular coordinates.

$(r, θ)$ $(r,theta)$ in polar coordinates is $(r cos θ, r sin θ)$ $(rcostheta,rsintheta)$ in rectangular coordinates.

Hence, $(4, \frac{3 π}{2})$ $(4,(3pi)/2)$ in polar coordinates in rectangular coordinates is

$(4 cos (\frac{3 π}{2}), 4 sin (\frac{3 π}{2}))$ $(4cos((3pi)/2),4sin((3pi)/2))$ or

$(4 \times 0, 4 \times (- 1))$ $(4xx0,4xx(-1))$ or $(0, - 4)$ $(0,-4)$

How do you convert (4, 3pi/2)(4,3π2) (4, 3pi/2) to rectangular form?