How do you factor $x^3 + 7x^2 + 15x + 9$ ?

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Answer 1 · 2016-03-11T15:06:11

$f(x) = (x + 1)(x + 3)^2$

Because (a - b + c - d) = 0, then f(-1) = 0. One factor is (x + 1).
After division -->
$f(x) = (x + 1)(x^2 + 6x + 9) =$
$f(x) = (x + 1)(x + 3)^2$

How do you factor x^3 + 7x^2 + 15x + 9x^3 + 7x^2 + 15x + 9?