How do you find three consecutive even integers if the sum of the first two minus the third is 16?

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Answer 1 · 2016-03-13T00:17:51

Express the condition in symbolic form and solve to find the three integers are:

#18, 20, 22#

Let the smallest of the three consecutive integers be #n#. Then the other two are #n+2# and #n+4#.

The condition in the question can be expressed:

#n + (n+2) - (n+4) = 16#

That simplifies to :

#n - 2 = 16#

Hence #n = 16+2 = 18#

So the three integers are #18#, #20#, #22#.