Question

How do you find two numbers whose difference is 4 and the difference of their square is 88?

Answer 1

`x=13`
`y=9`

Explanation:

How do you find two numbers whose difference is 4 and the difference of their square is 88?

Solution:

let `x=`the larger number
let `y=`the smaller number

`x-y=4`first equation
`x^2-y^2=88`second equation

Substitute the first in to the second equation

`x^2-y^2=88`second equation
`(y+4)^2-y^2=88`
`y^2+8y+16-y^2=88`
`8y=88-16`
`8y=72`
`y=9`

Solve for `x` using first equation

`x-y=4`first equation
`x-9=4`
`x=9+4`
`x=13`

God bless... I hope the explanation is useful.