Question

How do you solve for x in `x/(3-j) = (j/2)`?

Answer 1

`x= (3j - j^2)/2`

Explanation:

`x/ (3-j)= j/2`

Isolating `x` on the L.H.S:

`x= (j/2) * (3-j)`

`x= (3j - j^2)/2`