What is the the vertex of #y = x^2-14x+13#?

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Answer 1 · 2016-03-15T22:05:50

#(7, -36)#

#y = x^2-14x+13 = (x-7)^2-49+13 = (x-7)^2-36#

Slightly rephrasing:

#y = 1(x-7)^2+(-36)#

This is in standard vertex form:

#y = a(x-h)+k#

where #(h, k) = (7, -36)# is the vertex and #a=1# the multiplier.

graph{x^2-14x+13 [-15, 29.38, -44.64, -22.44]}