Question

How do you solve `x^2 – 6x -7 = 0`?

Answer 1

We can write this as follows

#x^2-6x-6-1=(x^2-1)-6(x+1)=(x-1)(x+1)-6(x+1)= (x+1)*(x-1-6)=(x+1)*(x-7)#

Now from `x^2-6x-7=0=>(x+1)*(x-7)=0` we get that the roots are

`x=-1`, `x=7`