Question

How do you find the derivative of `-2x(x^2+3)^-2`?

Answer 1

`d/dx=(6x^2-6)/((x^2+3)^3`

Explanation:

`f=-2x,g=(x^2+3)^-2`

`f'=-2,g'=-2(x^2+3)^-3 *2x`

`(df)/(dx)=(8x^2)/(x^2+3)^3 -2/((x^2+3)^2`

`(df)/(dx)=(8x^2-2(x^2+3))/((x^2+3)^3`

`(df)/(dx) = (8x^2-2x^2-6)/((x^2+3)^3`

`(df)/(dx)=(6x^2-6)/((x^2+3)^3`