How do you solve for x in #5ax-c=4c+ax #?
1 Answer
Mar 17, 2016
Explanation:
#5ax-c=4c+ax#
#5ax# #color(red)(-ax)-c=4c+ax# #color(red)(-ax)#
#4ax-c=4c#
#4ax-c# #color(blue)(+c)=4c# #color(blue)(+c)#
#4ax=5c#
#(4ax)/color(darkorange)(4a)=(5c)/color(darkorange)(4a)#
#color(green)(|bar(ul(color(white)(a/a)x=(5c)/(4a)color(white)(a/a)|)))#