A charge of 9 C is passing through points A and B on a circuit. If the charge's electric potential changes from 21 J to 12 J, what is the voltage between points A and B?

1 Answer
Mar 18, 2016

V_"AB"=-1 " V"

Explanation:

Delta W=q(V_B-V_A)
"it is done work ; if a charge is gone from one point to another"
V_B-V_A=V_"AB" " we can write"
Delta W=q*V_"AB"
Delta W=W_B-W_A
Delta W=12-21=-9 " J"
-9=9*V_"AB"
V_"AB"=-1 " V"