How do you factor $16 m + 4 n - 12 p$ $16m + 4n - 12p$ ?

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Answer 1 · 2016-03-19T14:43:49

$16 m + 4 n - 12 p = 4 (4 m + n - 3 p)$ $16m+4n-12p = 4(4m+n-3p)$

Without any more information about $m$ $m$ , $n$ $n$ and $p$ $p$ all you can do is separate out the common scalar factor $4$ $4$ as follows:

$16 m + 4 n - 12 p$ $16m+4n-12p$

$= (4 \cdot 4) m + 4 n - (4 \cdot 3) p$ $=(4*4)m+4n-(4*3)p$

$= 4 (4 m + n - 3 p)$ $=4(4m+n-3p)$

How do you factor 16m+4n−12p16m + 4n - 12p?