How do you write a standard form equation for the hyperbola with $9x^2 – y^2 – 36x + 4y + 23 = 0$ ?

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Answer 1 · 2016-03-20T06:29:05

$(x-2)^2 /1^2 - (y-2)^2/ 3^2 =1$

Rewrite, the equation as follows:

$9(x^2 -4x) -(y^2 -4y) +23=0$

$9(x^2-4x+4) -(y^2 -4y +4) -36 +4+23=0$

#9(x-2)^2 - (y-2)^2 = 9

$(x-2)^2 /1^2 - (y-2)^2/ 3^2 =1$

How do you write a standard form equation for the hyperbola with 9x^2 – y^2 – 36x + 4y + 23 = 09x^2 – y^2 – 36x + 4y + 23 = 0?