Question

What is the Cartesian form of `(-7,(11pi)/8)`?

Answer 1

Cartesian form of coordinates are `(2.6789,6.4673)`

Explanation:

Cartesian form of `(r,theta)` is `(rcostheta,rsintheta)`

Hence for `(-7, 11pi/8)`, it will be

`(-7cos(11pi/8), -7sin(11pi/8))`

As `cos(11pi/8)=-0.3827` and `sin(11pi/8)=-0.9239`

Hence cartesian form of coordinates are `(2.6789,6.4673)`