Question

How do you find the amplitude and period of a function `y = sin 2π/3 (x-6)`?

Answer 1

Amplitude is 1 and period is `(2pi)/((2pi/3))` = 3 radians.

Explanation:

The amplitude and the period for the sine wave

y = a sin (bx + c) are

a and `2pi/b`.

Here, a = 1 and b = `2pi/3`.