Question

How do you solve `log_7x=log_2 9`?

Answer 1

`x=477.59`

Explanation:

As `log_b x=log_ax/log_ab`, we have

`log_7 x=log_2 9` is `log_10x/log_10 7=log_10 9/log_10 2` i.e.

`logx/log7=log9/log2`

Hence `logx=(log9*log7)/log2=(0.9542*0.8451)/0.3010` or

`logx=2.679` or `x=10^(2.679)` or

`x=477.59`