How do you factor $x^{2} - x - 2 = 0$ $x^2-x-2=0$ ?

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Answer 1 · 2016-03-25T12:45:48

(x + 1)(x - 2)

y = x^2 - x - 2.
Find 2 numbers knowing sum (-1) and product (-2).
They are: 1 and -2.
y = (x + 1)(x - 2)

Shortcut.
Since a - b + c = 0, use shortcut. The 2real roots are (-1) and (-c/a = 2)
Therefor, the 2 factors are:
y = (x + 1)(x - 2)

How do you factor x2−x−2=0x^2-x-2=0?