How do you find the slope and intercept of $5 - \frac{1}{5} y = 10 x$ $5-1/5y=10x$ ?

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How do you find the slope and intercept of $5 - \frac{1}{5} y = 10 x$ $5-1/5y=10x$ ?

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Answer 1 · 2016-03-26T03:34:07

The slope, $m$ $m$ , is $- 50$ $-50$ .
The y-intercept, $b$ $b$ , is $25$ $25$ .
The x-intercept= $\frac{1}{2}$ $1/2$

Explanation:

The formula for the slope-intercept form of a linear equation is $y = m x + b$ $y=mx+b$ , where $m$ $m$ is the slope and $b$ $b$ is the y-intercept.

$5 - \frac{1}{5} y = 10 x$ $5-1/5y=10x$

In order to find the slope and y-intercept for the above formula, solve for $y$ $y$ .

Subtract $5$ $5$ from both sides.

$- \frac{1}{5} y = 10 x - 5$ $-1/5y=10x-5$

Simplify $- \frac{1}{5} y$ $-1/5y$ to $\frac{- 1 y}{5}$ $(-1y)/5$ .

$\frac{- 1 y}{5} = 10 x - 5$ $(-1y)/5=10x-5$

Multiply both sides by $5$ $5$ .

$- y = (10 x \cdot 5) - (5 \cdot 5)$ $-y=(10x*5)-(5*5)$

Simplify.

$- y = 50 x - 25$ $-y=50x-25$

Multiply both sides by $- 1$ $-1$ .

$y = - 50 x + 25$ $y=-50x+25$

$m = - 50$ $m=-50$
$b = 25$ $b=25$

If you wish to find the x-intercept also, substitute $0$ $0$ for $y$ $y$ and solve for $x$ $x$ .

$y = - 50 x + 25$ $y=-50x+25$

$0 = - 50 x + 25$ $0=-50x+25$

Add $50 x$ $50x$ to both sides.

$50 x = 25$ $50x=25$

Divide both sides by $50$ $50$ .

$x = \frac{25}{50}$ $x=25/50$

Simplify.

$x = \frac{1}{2}$ $x=1/2$

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How do you find the slope and intercept of $5 - \frac{1}{5} y = 10 x$ $5-1/5y=10x$ ?

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