A triangle has sides A, B, and C. Sides A and B are of lengths #7# and #1#, respectively, and the angle between A and B is #(5pi)/12 #. What is the length of side C?

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Answer 1 · 2016-03-26T04:32:39

side #c=6.81003#

From the given triangle
side #a=7# and side #b=1#
Angle #C=(5pi)/12#

We can solve this using Law of Cosines for sides

#c=sqrt(a^2+b^2-2*a*b*cos C)#

#c=sqrt(7^2+1^2-2*(7)*(1)*cos ((5pi)/12))#

#c=sqrt(49+1-14*cos ((5pi)/12))#

#c=sqrt(50-14*0.25881904510247)#

#c=6.81003#

God bless...I hope the explanation is useful.