How do you factor #8x^3-4x^2-2x+1#?
1 Answer
Mar 26, 2016
#8x^3-4x^2-2x+1=(2x-1)(2x+1)(2x-1)#
Explanation:
Factor by grouping and using the difference of squares identity:
#a^2-b^2 = (a-b)(a+b)#
with
#8x^3-4x^2-2x+1#
#=(8x^3-4x^2)-(2x-1)#
#=4x^2(2x-1)-1(2x-1)#
#=(4x^2-1)(2x-1)#
#=((2x)^2-1^2)(2x-1)#
#=(2x-1)(2x+1)(2x-1)#
