A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $33$ $33$ and the height of the cylinder is $13$ $13$ . If the volume of the solid is $32 π$ $32 pi$ , what is the area of the base of the cylinder?

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A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $33$ $33$ and the height of the cylinder is $13$ $13$ . If the volume of the solid is $32 π$ $32 pi$ , what is the area of the base of the cylinder?

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Answer 1 · 2016-03-27T09:07:25

$A = \frac{32 π}{24} = \frac{4}{3} π$ $A= (32pi)/24=4/3pi$

Explanation:

Volume of solid $V = A \times h_{c y} + \frac{1}{3} \times A \times h_{c o}$ $V = Axxh_(cy)+1/3xxAxxh_(co)$
Where
Area of cylnder = area of cone = A
Height of cylinder = $h_{c y} = 13$ $h_(cy)=13$
Height of cone = $h_{c o} = 33$ $h_(co)=33$
Volume of the solid $V = 32 π$ $V=32pi$
$:. 18pi= Axx13+1/cancel3xxAxxcancel33^11=24A$
$:. A= (32pi)/24=4/3pi$

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A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $33$ $33$ and the height of the cylinder is $13$ $13$ . If the volume of the solid is $32 π$ $32 pi$ , what is the area of the base of the cylinder?

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A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is 33 3333 and the height of the cylinder is 13 1313 . If the volume of the solid is 32 pi32π32 pi, what is the area of the base of the cylinder?

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Explanation:

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A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $33$ $33$ and the height of the cylinder is $13$ $13$ . If the volume of the solid is $32 π$ $32 pi$ , what is the area of the base of the cylinder?