An object with a mass of $15 kg$ is lying still on a surface and is compressing a horizontal spring by $5/6 m$ . If the spring's constant is $15 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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An object with a mass of $15 kg$ is lying still on a surface and is compressing a horizontal spring by $5/6 m$ . If the spring's constant is $15 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2016-03-30T05:55:44

$mu=0,085$

Explanation:

$F=u_k*Delta x$

$u_k=15 " "(kg)/s^2$

$Delta x=5/6 " "m$

$F=15*5/6=75/6=25/2" N"$

$F_f=mu* N"( Friction Force)"$
$mu:"coefficient of static friction"$
$N:"normal force to the contacting surfaces"$
$"we can write "N=m*g" (The Newton's third law)"$

$F=F_f$
$"m:15 kg"$
$25/2=mu*15*9,81$

$25=2*15*9,81* mu$

$25=294,3*mu$

$mu=25/(294,3)$

$mu=0,085$

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An object with a mass of $15 kg$ is lying still on a surface and is compressing a horizontal spring by $5/6 m$ . If the spring's constant is $15 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

1 Answer

Explanation:

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An object with a mass of 15 kg15 kg is lying still on a surface and is compressing a horizontal spring by 5/6 m5/6 m. If the spring's constant is 15 (kg)/s^215 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?

1 Answer

Explanation:

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An object with a mass of $15 kg$ is lying still on a surface and is compressing a horizontal spring by $5/6 m$ . If the spring's constant is $15 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?