Question

How do you solve for Kc in `7.2647 = -ln(Kc)`?

Answer 1

`K_c=e^(-7.2647)=0.0007`

Explanation:

`7.2647=-ln(K_c)`

`therefore ln(K_c)=-7.2647`

`thereforee^(ln(K_c))=e^(-7.2647)`

`therefore K_c=e^(-7.2647)=0.0007`.