Question

How do you use the intercepts to graph `-x+4y=8`?

Answer 1

You only need two points to draw a line graph,therefore, compute the intercepts `(-8, 0)` and `(0, 2)` then connect the two points.

Explanation:

From the given equation `-x+4y=8`, just set one variable to zero at a time then solve for the numerical value of the other.

Let us do it

`-x+4y=8`

Set `y=0" "`and then substitute that value in the equation

`-x+4(0)=8`

`-x+0=8`

`-x=8`

`(-x)/(-1)=8/(-1)`

and

`x=-8`
this means there is a point on the line at `(-8, 0)`

Now set `x=0` and then substitute that value in the equation

`-(0)+4y=8`

`0+4y=8`

`4y=8`

`(4y)/4=8/4`

`y=2`

this means there is another point on the line at `(0, 2)`

Now, to graph the `-x+4y=8`, you only need to draw a line from `(-8, 0)` to `(0, 2)`

Kindly see the graph of `-x+4y=8` and check the two points we calculated.

graph{-x+4y=8[-20,20,-10,10]}

God bless...I hope the explanation is useful.