How do you factor $x^{2} - 8 x + 6 x - 48$ $x^2 - 8x + 6x - 48$ ?

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Answer 1 · 2016-04-05T17:58:08

y = (x + 6)(x - 8)

$y = x^{2} - 2 x - 48$ $y = x^2 - 2x - 48$ .
Find 2 numbers knowing sum (-2) and product (-48).
They are 6 and -8.
y = ( x + 6)(x - 8)

How do you factor x2−8x+6x−48x^2 - 8x + 6x - 48?