Question

A charge of `6 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `36 J` to `33 J`, what is the voltage between points A and B?

Answer 1

`V_"AB"=-0,5V`

Explanation:

`q=6C`
`W_A=36 J`
`W_B=33J`
`Delta W=W_B-W_A=33-36=-3J`

`Delta W=q(V_B-V_A)`
`V_B-V_A=V_"AB"`

`Delta W=q*V_"AB"`
`-3=6*V_"AB"`

`V_"AB"=-3/6`

`V_"AB"=-0,5V`