Question

What is `f(x) = int x^3-2x dx` if `f(-2)=-1`?

Answer 1

`f(x)=int(x^3-2x)dx`

`=x^4/4-(2x^2)/2+C`

Now applying the initial boundary condition we get

`f(-2)=-1=>C=-1`

`therefore f(x)=1/4x^4-x^2-1`