What is the vertex of #y= 2x^2+16x + 12#?

1 Answer
Apr 10, 2016

vertex: #(x,y)=(-4,-20)#

Explanation:

Convert the given: #y=2x^2+16x+12#
into general vertex form: #y=color(green)(m)(x-color(red)(a))^2+color(blue)(b)# with vertex at #(color(red)(a),color(blue)(b))#

#y=2(x^2+8x)+12

#y=2(x^2+8xcolor(blue)(+4^2))+12 color(blue)(-2(4^2))#

#y=2(x+4)^2-20#

#y=color(green)(2)(x-color(red)(color(white)("")(-4)))^2+color(blue)(color(white)(""X)(-20))#

#color(white)("XXXXXX")#with vertex at #(color(red)(color(white)("")(-4)),color(blue)(color(white)("")(-20)))#
graph{2x^2+16x+12 [-16.64, 8.68, -21.69, -9.03]}