How do you graph |y|= 6- |3x|?

1 Answer
Apr 10, 2016

|y|>=0 to |x|<=2. Draw the four straight lines y=+-3x+-6. The periphery of the so formed rhombus, with vertices at (+-2, 0) and (0, +-6), is the graph for the given equation.

Explanation:

|y|>=0 to |3x|<=6 to |x|<=2.

The given equation is the compounded equation for the quadruplet +-y=6+-3x to y=+-3x+-6.

These lines, in pairs, meet at (+-2, 0) and (0, +-6) and form a rhombus. of side sqrt40..

The rhombus reaches the limits x=+-2, from within.

Only the coordinates (x, y) of points on this rhombus are governed by the given equation. The rhombus is the graph.