How do you factor completely #8x^2 - 14x + 3#?
1 Answer
Apr 11, 2016
#(2x-3)(4x-1)#
Explanation:
Given -
#8x^2-4x+3#
#8x^2-2x-12x+3#
#2x(4x-1)-3(4x-1)#
#(2x-3)(4x-1)#
#(2x-3)(4x-1)#
Given -
#8x^2-4x+3#
#8x^2-2x-12x+3#
#2x(4x-1)-3(4x-1)#
#(2x-3)(4x-1)#