How do you factor $x^{3} - 3 x^{2} + x - 3$ $x^3-3x^2+x-3$ ?

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Answer 1 · 2016-04-11T12:19:39

$(x - 3) (x^{2} + 1)$ $(x-3)(x^2+1)$

$x^{3} - 3 x^{2} + x - 3 = x^{2} (x - 3) + 1 (x - 3) = (x - 3) (x^{2} + 1)$ $x^3-3x^2+x-3 = x^2(x-3)+1(x-3)=(x-3)(x^2+1)$ [Ans]

How do you factor x^3-3x^2+x-3x3−3x2+x−3x^3-3x^2+x-3?