Question

What is the axis of symmetry and vertex for the graph `y = 2x^2 - 8x + 10`?

Answer 1

The axis of symmetry is `x=2` and vertex is at `(2,2)`

Explanation:

#y=2x^2-8x+10 = 2(x^2-4x+4)+10-8=2(x- **2** )^2+ **2** The vertex is at #(2,2)`and the axis of symmetry is`x=2# graph{2x^2-8x+10 [-10, 10, -5, 5]}[Ans]

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`y=2x^2-8x+10 = 2(x^2-4x+4)+10-8=2(x- 2 )^2+ 2`
The vertex is at `(2,2)` and the axis of symmetry is `x=2`