How do you write the equation of the line with point P(-10,1) with slope -5?

1 Answer
Apr 25, 2016

#y - 1 = -5(x + 10)#

Explanation:

Use the point-slope form:
#y - y_1 = m(x- x_1)#

We know that in the slope-intercept formula (#y = mx +b#), the #m# value is the slope. Similarly, in point-slope form, the #m# is also the slope.

We are given that the slope is equal to -5. Also, there's point P(-10,1). The part where we have #y_1# and #x_1#, we can replace it with the corresponding x- and y-coordinates. The x-coordinate in this case would be -10 and the y-ccordinate in this case would be 1. Let's substitute all of these values into its corresponding area in the formula.

#y - 1 = -5(x - (-10))#
Which can also be written as #y - 1 = -5(x+ 10)#