How do you write an equation in slope intercept form of a line containing the coordinates (10,-12) and (13,18)?

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Answer 1 · 2016-04-27T11:53:36

#y=10x-112#

We start with the points:

#(10,-12); (13,18)#

We are trying to get the equation in the form

#y=mx+b#

where #m# is the slope which we calculate using the rise over the run:

#m =( -12-18)/(10-13) = -30/-3 = 10#

so the equation becomes

#y=10x+b#

We can determine the y-intercept, #b#, by substituting either known point into this equation - let's use the point #(10,-12)#

#-12=100+b implies b=-112#

We can now graph the equation:

#y=10x-112#

graph{(y-10*x+112)=0 [-60, 60, -19, 21]}