How do you simplify #sqrt85#?
1 Answer
Explanation:
The prime factorisation of
#85 = 5 * 17#
This contains no square factors, so
If you wish, you can factor it as:
#sqrt(85) = sqrt(5)sqrt(17)#
but I don't think that counts as simplification.
The general idea is that if a radicand contains square factors then it can be simplified. For example:
#sqrt(24) = sqrt(2^2*6) = sqrt(2^2)sqrt(6) = 2sqrt(6)#
If it has no square factors then this kind of simplification is not possible.
Random Bonus
Any square root is expressible as a repeating continued fraction. in our example:
#sqrt(85) = [9;bar(4,1,1,4,18)]#
#=9+1/(4+1/(1+1/(1+1/(4+1/(18+1/(4+1/(1+1/(1+1/(4+1/(18+...))))))))))#
You can truncate the continued fraction to give you rational approximations for the square root.
For example:
#sqrt(85) ~~ [9;4] = 9+1/4 = 37/4 = 9.25#
#sqrt(85) ~~ [9;4,1,1,4] = 9+1/(4+1/(1+1/(1+1/(4)))) = 378/41 = 9.bar(21951)#
Actually