How do you solve #(x-2)^2=-3#?
1 Answer
May 1, 2016
Explanation:
To solve this we want to take the square root of both sides, but the right hand side is negative. If
If
So given:
#(x-2)^2 = -3 = (sqrt(3)i)^2#
We must have:
#x-2 = +-sqrt(3)i#
Note the
Then adding
#x = 2+-sqrt(3)i#