Simplify this expression: #[(12-:4 + 9-:1 + 15:5) · 2 – (1+1+8+16+1)] -: 3 #? Prealgebra Fractions Equivalent Fractions and Simplifying 1 Answer Shwetank Mauria May 3, 2016 #[(12-:4+9-:1+15-:5)*2-(1+1+8+16+1)]-:3=1# Explanation: #[(12-:4+9-:1+15-:5)*2-(1+1+8+16+1)]-:3# = #[(3+9+3)*2-(27)]-:3# = #[15*2-27]-:3# = #[30-27]-:3# = #3-:3# = #1# Answer link Related questions What is 0.098 divided by 7? How do you find the fraction notation and simplify 16.6%? How do you convert #0.bar(45)# (meaning the #45# is being repeated) to a fraction? How do you convert 0.40 (40 repeating) to a fraction? How do you convert 8/15 to a decimal? How do you express #3/4, 7/16,# and #5/8# with the #LCD#? How do you simplify fractions? What is the simplified form of #30/42#? How do you subtract and simplify #9-5 1/3#? How do you add and simplify #5/7 + 3/4#? See all questions in Equivalent Fractions and Simplifying Impact of this question 2732 views around the world You can reuse this answer Creative Commons License