Question

What the is the polar form of `y = y/x+x(2-y)^2`?

Answer 1

`rsintheta=tantheta+rcostheta(2-rsintheta)^2`

Explanation:

If `(r,theta)` is in polar form and `(x,y)` in Cartesian form the relation between them is as follows:

`x=rcostheta`, `y=rsintheta`, `r^2=x^2+y^2` and `tantheta=y/x`

Hence, `y=y/x+x(2-y)^2` can be written as

`rsintheta=(rsintheta)/(rcostheta)+rcostheta(2-rsintheta)^2`

or `rsintheta=tantheta+rcostheta(2-rsintheta)^2`