How do you multiply #(x+6)(x+1)#?

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Answer 1 · 2016-05-04T08:58:59

#x^2+7x+6#

The proper name for what I am about to show you is the property of being 'distributive'.

As a first step example: suppose we had #2(x+5)# then you multiply everything inside the bracket by 2 so you end up with #2x+10#

Given#" "color(blue)((x+6)color(brown)((x+1))#

Write as:

#color(blue)(x)color(brown)((x+1))color(blue)(+6color(brown)((x+1))" "# This is the result of being 'distributive'.
#" "#Notice the + follows the 6.

Multiply everything inside the brackets by what is outside it.

#x^2+x+6x+6#

#x^2+7x+6#