How do you solve for x in #4/9( x + 3 ) = g#?

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Answer 1 · 2016-05-06T14:47:19

# color(green)(x = (9g-12)/4 #

#color(green)(4 / 9) ( x +3 ) = g#

# ( x +3 ) = g * color(green)( (9 / 4)#

# color(blue)(x) +3 = (9g)/4#

Isolating #color(blue)(x)#

# color(blue)(x) = (9g)/4 - 3#

# color(blue)(x) = (9g)/4 - 12/4#

# color(blue)(x = (9g-12)/4 #