A model train with a mass of #5 kg# is moving along a track at #14 (cm)/s#. If the curvature of the track changes from a radius of #7 cm# to #24 cm#, by how much must the centripetal force applied by the tracks change?

Question

1160 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-07T07:34:52

A change of #Delta F=119/120=0.9916666" "#Newton

Given data: #v=14" "#cm/second#=0.14" "#meter/second
#m=5" "#kilogram
#r_1=7" "#centimeter#=.07" "#meter
#r_2=24" "#centimeter#=0.24" "#meter

Centripetal Force formula

#F_1=(mv^2)/r_1=(5*(.14)^2)/(.07)=7/5" "#Newtons

#F_2=(mv^2)/r_2=(5*(.14)^2)/(.24)=49/120" "#Newtons

#F_1-F_2=Delta F=119/120=0.9916666" "#Newton

God bless....I hope the explanation is useful.