How do you write the equation of the line containing the point (-2,-1) parallel to y=-3/2x-1?

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Answer 1 · 2016-05-07T09:25:30

#y=-3/2x-4#

Equation of the given line -

#y=-3/2x-1#
Slope of the line
#m_1=-3/2#

Parallel line's slope is #m_1=m_2#
Hence, the slope of the parallel line is

#m_2=-3/2#

The parallel line is passing through the point #(-2, -1)#

Find the equation of the line-

#y=mx+c#
#-1=-3/2 .(-2)+c#
#-1=6/2+c=3+c#

By trnspose, we get,

#3+c=-1#
#c=-1-3=-4#
Then the equation is-
#y=-3/2x-4#