What is the net area between $f (x) = tan x$ $f(x)=tanx$ in $x \in [0, \frac{π}{3}]$ $x in[0,pi/3]$ and the x-axis?

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What is the net area between $f (x) = tan x$ $f(x)=tanx$ in $x \in [0, \frac{π}{3}]$ $x in[0,pi/3]$ and the x-axis?

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Answer 1 · 2016-05-08T08:50:03

$A = \int_{0}^{\frac{π}{3}} tan x d x = {[log (| sec (x) |)]}_{0}^{\frac{π}{3}} \approx 0.693$ $A= int_0^(pi/3) tanx dx = [log(abs(sec(x)))]_0^(pi/3) ~~0.693$

Explanation:

GIven : $f (x) = tan x : \to x \in [0, \frac{π}{3}]$ $f(x)=tanx: ->x in[0,pi/3]$

Required : Area under $f (x) and the x axis$ $f(x) " and the " x " axis"$

Solution: Straight integration of $f (x)$ $f(x)$ in the interval $[0, \frac{π}{3}]$ $[0, pi/3]$

$A = \int_{0}^{\frac{π}{3}} tan x d x = {[log (| sec (x) |)]}_{0}^{\frac{π}{3}} \approx 0.693$ $A= int_0^(pi/3) tanx dx = [log(abs(sec(x)))]_0^(pi/3) ~~0.693$

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What is the net area between $f (x) = tan x$ $f(x)=tanx$ in $x \in [0, \frac{π}{3}]$ $x in[0,pi/3]$ and the x-axis?

1 Answer

Explanation:

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What is the net area between f(x)=tanxf(x)=tanxf(x)=tanx in x in[0,pi/3] x∈[0,π3]x in[0,pi/3] and the x-axis?

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Explanation:

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What is the net area between $f (x) = tan x$ $f(x)=tanx$ in $x \in [0, \frac{π}{3}]$ $x in[0,pi/3]$ and the x-axis?