Question

A charge of `2 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `28 J` to `24 J`, what is the voltage between points A and B?

Answer 1

`V_"AB"=-2V`

Explanation:

`q=2C`
`Delta W=24-28=-4J`
`V_B-V_A=V_"AB"`
`Delta W=V_"AB"*q`
`-4=V_"AB"*2`
`V_"AB"=-4/2`
`V_"AB"=-2V`