How do you find the amplitude, period, and shift for #y = 3sin(2x + pi/4)#?

1 Answer

It isn't too complicated.

Explanation:

The amplitude, which can be referred to as the variable #a#, is the number before your trig function (sin,cos, etc.). In this case, the amplitude is #3#, since it is before the sin.

The number after sin and before #x# is known as the variable #b#. To find the period of a sin function, just do: #(2pi)/b#.

The period for this particular problem would turn out to be #pi#, since #b# is #2# (from inside the parentheses) and #(2pi)/2# is just #pi#.

The shift is how much you move your graph left and right. If it is a positive number in the parentheses, you move the graph left. If it is negative, you move it right.

You move the graph left/right as many units as shown, in this case it is left #pi/4# units. That would determine your horizontal shift.

Hope this helped!