How do you factor the expression $x^{3} - 3 x^{2} - 4 x + 12$ $x^3-3x^2-4x+12$ ?

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How do you factor the expression $x^{3} - 3 x^{2} - 4 x + 12$ $x^3-3x^2-4x+12$ ?

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Answer 1 · 2016-05-10T21:32:31

$x^{3} - 3 x^{2} - 4 x + 12 = (x - 2) (x + 2) (x - 3)$ $x^3-3x^2-4x+12=(x-2)(x+2)(x-3)$

Explanation:

Factor by grouping:

$x^{3} - 3 x^{2} - 4 x + 12$ $x^3-3x^2-4x+12$

$= (x^{3} - 3 x^{2}) - (4 x - 12)$ $=(x^3-3x^2)-(4x-12)$

$= x^{2} (x - 3) - 4 (x - 3)$ $=x^2(x-3)-4(x-3)$

$= (x^{2} - 4) (x - 3)$ $=(x^2-4)(x-3)$

$= (x - 2) (x + 2) (x - 3)$ $=(x-2)(x+2)(x-3)$

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How do you factor the expression $x^{3} - 3 x^{2} - 4 x + 12$ $x^3-3x^2-4x+12$ ?

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