Question

How do you convert `4x²+y²-8x+4y-9=0` into standard form?

Answer 1

Perform a double completion of squares.

Explanation:

`4(x^2 - 2x + 1 - 1) + (y^2 + 4 + 4 - 4) - 9 = 0`

`4(x - 1)^2 - 4 +(y + 2)^2 - 4 - 9 = 0`

`4(x - 1)^2 + (y + 2)^2 = 17`

Hopefully this helps!